document.write( "Question 880409: Find the area under the curve for the function f(x)= 4x^3+3x^2-x+1 on the interval [1,2]. \n" ); document.write( "
Algebra.Com's Answer #531405 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi
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document.write( "Area under curve:  
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document.write( "\"int%28+4x%5E3%2B3x%5E2-x%2B1%2C+dx%2C+1%2C+2%29\"
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document.write( "g(x) = x^4 + x^3 -x^2/2 + x from 1 to 2
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document.write( "Area under curve: g(2) - g(1) = 24 - 2.5 = 21.5 \n" );
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