document.write( "Question 74142This question is from textbook Algebra 2
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document.write( ": I am trying to figure out what y=-4x^2+8x-1 in vertex form would be.\r
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document.write( "I know that I need to complete the square. I think I am supposed to add 1 and then balance it by subtracting 1? ((-2/2)^2=1)\r
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document.write( "y=(-4x^2+8x+1)-1+1. \r
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document.write( "Is that what I was supposed to do? If so, how do I write that as a perfect square to get the vertex form? Please help! \n" );
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Algebra.Com's Answer #53140 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! y=-4x^2+8x-1 in vertex form \n" ); document.write( "Vertex form is y=(x-h)^2+k, where (h,k)=vertex \n" ); document.write( "y=-4(x^2-2x+___)+4(__)-1 \n" ); document.write( "y=-4(x^2-2x+(-2/2)^2)+4(-2/2)^2-1 \n" ); document.write( "y=-4(x^2-2x+(-1)^2)+4(-1)^2-1 \n" ); document.write( "y=-4(x^2-2x+1)+4(1)-1 \n" ); document.write( "y=-4(x-1)^2+3 \n" ); document.write( "The vertex is now easily determined to be: (1,3) \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |