document.write( "Question 880209: The sum of the digits of a two-digit no. is 11. If the digits are reversed the new no. is 7 more than twice the original no. Find the original no.
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Algebra.Com's Answer #531391 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The sum of the digits of a two-digit no. is 11. If the digits are reversed the new no. is 7 more than twice the original no. Find the original no. \n" ); document.write( "*** \n" ); document.write( "u=units digit \n" ); document.write( "t=tens digit \n" ); document.write( "u+t=11 \n" ); document.write( "t=11-u \n" ); document.write( ".. \n" ); document.write( "10u+t=2(10t+u)+7 \n" ); document.write( "10u+t=20t+2u+7 \n" ); document.write( "10u+11-u=20(11-u)+2u+7 \n" ); document.write( "9u+11=220-20u+2u+7 \n" ); document.write( "27u=216 \n" ); document.write( "u=8 \n" ); document.write( "t=11-u=3 \n" ); document.write( "original number=10t+u=38 \n" ); document.write( " |