document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74140>Question 74140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean theorem to determine the length of each line segment. Where appropriate, round to the nearest hundredth.\r<BR>\n" );
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document.write( "The plotted points are at (1, -1) and (3, 2).\r<BR>\n" );
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document.write( "I am not understanding this problem and need some help with this. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53138 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To define the right triangle we need to calculate the x & y distances. Thus:<BR>\n" );
document.write( "The x distance is 3-1=2<BR>\n" );
document.write( "The y distance is 2-(-1), 2+1=3<BR>\n" );
document.write( "So we have the formula x^2+y^2=h^2 h being the hypotenuse.<BR>\n" );
document.write( "2^2+3^2=h^2<BR>\n" );
document.write( "4+9=h^2<BR>\n" );
document.write( "13=h^2 now calculate the sqrt of 13 & h.<BR>\n" );
document.write( "3.6=h is the hypotenuse or the distance between these two points.<BR>\n" );
document.write( "To become familiar with this concept use graph paper, plot the two points, draw the triangle and measure the hypotenuse (distance between these two points).<BR>\n" );
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