document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=880321>Question 880321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When the sum of twice the number and three is subtracted from 6, the result is equal to ten minus that number. Find the number.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531360 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n = the number.<BR>\n" );
document.write( "The problem statement reduces to the equation<BR>\n" );
document.write( "(1) 6 - (2n+3) = 10 -n<BR>\n" );
document.write( "Now solve for n<BR>\n" );
document.write( "(2) 6 - 2n - 3 = 10 - n or<BR>\n" );
document.write( "(3) 3 - 10 = 2n - n or<BR>\n" );
document.write( "(4) -7 = n or<BR>\n" );
document.write( "(5) n = -7 Check this using (1).<BR>\n" );
document.write( "Is (6-(2*(-7)+3) = 10 -(-7))?<BR>\n" );
document.write( "Is (6-(-14+3) = 10 + 7)?<BR>\n" );
document.write( "Is (6-(-11) = 17)?<BR>\n" );
document.write( "Is (6+11 = 17)?<BR>\n" );
document.write( "Is (17 = 17)? Yes<BR>\n" );
document.write( "Answer: the number is -7. </SPAN>\n" );
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