document.write( "Question 880269: The perimeter of a rectangle is 800 yards. What are the dimensions of the rectangle if the length is 90 yards more than the width? \n" ); document.write( "
Algebra.Com's Answer #531319 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( " .
\n" ); document.write( "L + w = 400 yd
\n" ); document.write( "(w+90) + w = 400
\n" ); document.write( " 2w = 310
\n" ); document.write( " e = 155 yd and L is 245 yd \"155%2B90\" \n" ); document.write( "
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