document.write( "Question 880289: for what real values of x and y are the numbers -3+i^2 y and x^2+y+4i are conjugate complex \n" ); document.write( "
Algebra.Com's Answer #531316 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "-3+i²y and x²+y+4i\r\n" ); document.write( "\r\n" ); document.write( "Since i² = -1, which is a real number, the first one is\r\n" ); document.write( "a real number but the second one is imaginary, so it is \r\n" ); document.write( "impossible for them to be conjugates!\r\n" ); document.write( "\r\n" ); document.write( "That's because -3+i²y = -3+(-1)y = -3-y which is a \r\n" ); document.write( "real number and therefore it has no imaginary part. \r\n" ); document.write( "\r\n" ); document.write( "However x²+y+4i has an imaginary part, 4i.\r\n" ); document.write( "\r\n" ); document.write( "Therefore no possible real numbers x and y will cause\r\n" ); document.write( "\r\n" ); document.write( "-3+i²y and x²+y+4i to be conjugate comlex numbers, for\r\n" ); document.write( "if a complex number has an imaginary part, its conjugate\r\n" ); document.write( "must also have an imaginary part.\r\n" ); document.write( "\r\n" ); document.write( "Are you sure you copied the problem correctly?\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |