document.write( "Question 880225: A bowl contains 5 pieces of red candy, 6 pieces of green, and 11 pieces of blue. Two pieces are drawn and replaced back into the bowl. What is the probability of drawing from the bowl a piece of red candy and a piece of green candy.
\n" ); document.write( "a. 21/242 b. 101/242 c. 15/242 d. 203/242 \n" ); document.write( "

Algebra.Com's Answer #531278 by Fombitz(32388) $\"\"$ $\"About$

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\n" ); document.write( " $\"RR=%285%2F22%29%285%2F22%29=25%2F484\"$
\n" ); document.write( " $\"RG=%285%2F22%29%286%2F22%29=30%2F484\"$
\n" ); document.write( " $\"RB=%285%2F22%29%2811%2F22%29=55%2F484\"$
\n" ); document.write( " $\"GR=%286%2F22%29%285%2F22%29=30%2F484\"$
\n" ); document.write( " $\"GG=%286%2F22%29%286%2F22%29=36%2F484\"$
\n" ); document.write( " $\"GB=%286%2F22%29%2811%2F21%29=66%2F484\"$
\n" ); document.write( " $\"BR=%2811%2F22%29%285%2F21%29=55%2F484\"$
\n" ); document.write( " $\"BG=%2811%2F22%29%286%2F21%29=66%2F484\"$
\n" ); document.write( " $\"BB=%2811%2F22%29%2811%2F21%29=121%2F484\"$
\n" ); document.write( "If you add them you will find that them sum to $\"484%2F484\"$ or $\"1\"$ .
\n" ); document.write( "So the probability of $\"R\"$ then $\"G\"$ are,
\n" ); document.write( " $\"P%28RG%29=30%2F484=15%2F242\"$ \r
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