document.write( "Question 880014: a boat goes 16 km upstream and 24 km downstream in 6 hours. it also covers 12 km upstream and 36 km downstream in same time. find the rate of speed still in water and stream. \n" ); document.write( "
Algebra.Com's Answer #531234 by ankor@dixie-net.com(22740)\"\" \"About 
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a boat goes 16 km upstream and 24 km downstream in 6 hours.
\n" ); document.write( " it also covers 12 km upstream and 36 km downstream in same time.
\n" ); document.write( " find the rate of speed still in water and stream.
\n" ); document.write( ":
\n" ); document.write( "Let s = rate of speed in still water
\n" ); document.write( "let c = rate of the current
\n" ); document.write( "then
\n" ); document.write( "(s-c) = effective speed upstream
\n" ); document.write( "and
\n" ); document.write( "(s+c) = effective speed downstream
\n" ); document.write( ":
\n" ); document.write( "Write a time equation for each trip, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "\"16%2F%28%28s-c%29%29\" + \"24%2F%28%28s%2Bc%29%29\" = 6
\n" ); document.write( "and
\n" ); document.write( "\"12%2F%28%28s-c%29%29\" + \"36%2F%28%28s%2Bc%29%29\" = 6
\n" ); document.write( "Simplify both equations, divide the 1st by 2, the 2nd by 3 and we have
\n" ); document.write( "\"8%2F%28%28s-c%29%29\" + \"12%2F%28%28s%2Bc%29%29\" = 3
\n" ); document.write( "\"4%2F%28%28s-c%29%29\" + \"12%2F%28%28s%2Bc%29%29\" = 2
\n" ); document.write( "----------------------------------------Subtraction eliminates (s+c)
\n" ); document.write( "\"4%2F%28%28s-c%29%29\" + 0 = 1
\n" ); document.write( "4 = s - c
\n" ); document.write( "(c+4) = s
\n" ); document.write( "Using the first original equation replace s with (c+4)
\n" ); document.write( "\"16%2F%28%28%28c%2B4%29-c%29%29\" + \"24%2F%28%28%28c%2B4%29%2Bc%29%29\" = 6
\n" ); document.write( "\"16%2F4\" + \"24%2F%28%282c%2B4%29%29\" = 6
\n" ); document.write( "4 + \"24%2F%28%282c%2B4%29%29\" = 6
\n" ); document.write( "\"24%2F%28%282c%2B4%29%29\" = 6 - 4
\n" ); document.write( "\"24%2F%28%282c%2B4%29%29\" = 2
\n" ); document.write( "24 = 2(2c + 4)
\n" ); document.write( "24 = 4c + 8
\n" ); document.write( "24 - 8 = 4c
\n" ); document.write( "c = 16/4
\n" ); document.write( "c = 4 mph is the rate of the stream
\n" ); document.write( "and
\n" ); document.write( "s = c+4
\n" ); document.write( "s = 4 + 4
\n" ); document.write( "s = 8 mph is the rate in still water\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that checks out in the 2nd equation
\n" ); document.write( "\"12%2F4%29\" + \"36%2F12\" = 6
\n" ); document.write( "3 + 3 = 6
\n" ); document.write( "
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