document.write( "Question 74029: Geometric and Binomial trials
\n" ); document.write( "Geometric: E(X)=1/p SD(X)=square root of q/p^2
\n" ); document.write( "Binomial: E(X)=np SD(X)=square root of npq\r
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\n" ); document.write( "\n" ); document.write( "1. in a bowling league, the mean score for men is 154 qith a standard deviation(SD) of 9...for women it is a mean of 144 with a standard deviation of 12. at the end, they randomly pair men and women as opponets
\n" ); document.write( "a)what is the expected total of men and women pairs?\r
\n" ); document.write( "\n" ); document.write( "b)what is the Standard Deviation of the sum of the pairs?\r
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\n" ); document.write( "\n" ); document.write( "2. 18% of adults are smokers
\n" ); document.write( "a)they selected a few adults at random to find out if they are smokers. explain why this is a Bernoulli trial?\r
\n" ); document.write( "\n" ); document.write( "b)how many people do you expect to ask to find a smoker?\r
\n" ); document.write( "\n" ); document.write( "c)whats the probability that there are at least 8 smokers among a sample of 30 people?\r
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\n" ); document.write( "\n" ); document.write( "3. 70% of drivers wear seatbelts. there was a random sample of 500 drivers taken.
\n" ); document.write( "a)use a Binomial model to find the probablity that at least 350 drivers are wearing seatbelts?\r
\n" ); document.write( "\n" ); document.write( "b)use a Binomial model to find the probablity that no more than 400 drivers are wearing seatbelts?\r
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\n" ); document.write( "\n" ); document.write( "im very lost on these problems so if you could help, id be so greatful!
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Algebra.Com's Answer #53123 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Geometric and Binomial trials
\n" ); document.write( "Geometric: E(X)=1/p; SD(X)=square root of q/p^2
\n" ); document.write( "Binomial: E(X)=np; SD(X)=square root of npq \r
\n" ); document.write( "\n" ); document.write( "1. in a bowling league, the mean score for men is 154 with a standard deviation(SD) of 9...for women it is a mean of 144 with a standard deviation of 12. at the end, they randomly pair men and women as opponets
\n" ); document.write( "a)what is the expected total score of men and women pairs?
\n" ); document.write( "For the men:
\n" ); document.write( "mean=np = 154; std=sqrt(npq)=9
\n" ); document.write( "So, std=sqrt(154q)=9
\n" ); document.write( "Square both sides to get 154q=81
\n" ); document.write( "q=81/154; therefore p=73/154
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\n" ); document.write( "For the women:
\n" ); document.write( "mean=np=144; std=sqrt12
\n" ); document.write( "So, std=sqrt(144q)=12
\n" ); document.write( "Square both sides to get 144q=144
\n" ); document.write( "q=1 and p=0
\n" ); document.write( "COMMENT: This does not make sense.
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\n" ); document.write( "\n" ); document.write( "b)what is the Standard Deviation of the sum of the pairs?
\n" ); document.write( "If std=9, Var=81
\n" ); document.write( "If std=12, Var=144
\n" ); document.write( "std(men+women)=sqrt(81+144)= 15
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\n" ); document.write( "\n" ); document.write( "2. 18% of adults are smokers
\n" ); document.write( "a)they selected a few adults at random to find out if they are smokers. explain why this is a Bernoulli trial?
\n" ); document.write( "Two possible outcomes: smoker or no smoker
\n" ); document.write( "Smoking among the people selected may not be independent but they
\n" ); document.write( "are less then 10% of the total population.
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\n" ); document.write( "b)how many people do you expect to ask to find a smoker?
\n" ); document.write( "???????
\n" ); document.write( "c)whats the probability that there are at least 8 smokers among a sample of 30 people?
\n" ); document.write( "n=30,p=0.18,X>=8
\n" ); document.write( "If you have a TI calculator use [1- binomcdf(30,0.18,7)]=0.158...
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\n" ); document.write( "\n" ); document.write( "3. 70% of drivers wear seatbelts. there was a random sample of 500 drivers taken.
\n" ); document.write( "a)use a Binomial model to find the probablity that at least 350 drivers are wearing seatbelts?
\n" ); document.write( "n=500; p=0.7; X>=350
\n" ); document.write( "Use [1-binomcdf(500,0.7,349)]=0.522
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\n" ); document.write( "b)use a Binomial model to find the probablity that no more than 400 drivers are wearing seatbelts?
\n" ); document.write( "X<=400
\n" ); document.write( "Use binomcdf(500,0.7,400)=0.999999
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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