document.write( "Question 9809: 3. Candy and Tim share a paper route. It takes Candy 70 minutes to deliver all the papers, whereas Tim takes 80 minutes. How long does it take them when they work together? \n" ); document.write( "
Algebra.Com's Answer #5312 by rapaljer(4671)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let x = time it takes them to do the paper route together.\r
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\n" ); document.write( "\n" ); document.write( "This means that in 1 minute, together they can do \"1%2Fx+\" of the paper route.\r
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\n" ); document.write( "\n" ); document.write( "In 1 minute working alone, Candy can do 1/70th of the route, and in 1 minute working alone, Tim can do 1/80th of the route. \r
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\n" ); document.write( "\n" ); document.write( "The equation is that the part Candy can do in 1 minute + the part that time can do in 1 minute = the part they can do together in 1 minute:\r
\n" ); document.write( "\n" ); document.write( "\"1%2F70+%2B+1%2F80+=+1%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "The LCD is 560x, so multiply both sides of the equation by 560x:
\n" ); document.write( "\"%28560x%29+%2A%281%2F70%29+%2B+%28560x%29%2A%281%2F80%29+=+%28560x%29%2A+%281%2Fx%29+\"
\n" ); document.write( "\"8x+%2B+7x+=+560\"
\n" ); document.write( "\"15x+=+560\"
\n" ); document.write( "\"x+=+560%2F15\"= 37.3 minutes.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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