document.write( "Question 879991: If a scooterist drives at the rate of 24km/hr, he reaches his destination 5 minutes too
\n" ); document.write( "late. If he drives at the rate of 30km/hr, he reaches his destination 4 minutes too soon.
\n" ); document.write( "How far is his destination ?
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Algebra.Com's Answer #531191 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = the distance he travels
\n" ); document.write( "Let \"+t+\" = the \" on time \" time
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\n" ); document.write( "(1) \"+d+=+24%2A%28+t+%2B+5%2F60+%29+\"
\n" ); document.write( "(2) \"+d+=+30%2A%28+t+-+4%2F60+%29+\"
\n" ); document.write( "-------------------------
\n" ); document.write( "By substitution:
\n" ); document.write( "\"+24%2A%28+t+%2B+1%2F12+%29+=+30%2A%28+t+-+1%2F15+%29+\"
\n" ); document.write( "\"+24t+%2B+24%2F12+=+30t+-+30%2F15+\"
\n" ); document.write( "\"+6t+=+2+%2B+2+\"
\n" ); document.write( "\"+t+=+2%2F3+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+=+24%2A%28+t+%2B+5%2F60+%29+\"
\n" ); document.write( "(1) \"+d+=+24%2A%28+2%2F3+%2B+5%2F60+%29+\"
\n" ); document.write( "(1) \"+d+=+24%2A%28+40%2F60+%2B+5%2F60+%29+\"
\n" ); document.write( "(1) \"+d+=+24%2A%28+45%2F60+%29+\"
\n" ); document.write( "(1) \"+d+=+24%2A%28+3%2F4+%29+\"
\n" ); document.write( "(1) \"+d+=+18+\"
\n" ); document.write( "The destination is 18 km away
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+24%2A%28+t+%2B+5%2F60+%29+\"
\n" ); document.write( "(1) \"+18+=+24%2A%28+40%2F60+%2B+5%2F60+%29+\"
\n" ); document.write( "(1) \"+18%2F24+=+45%2F60+\"
\n" ); document.write( "(1) \"+3%2F4+=+3%2F4+\"
\n" ); document.write( "OK
\n" ); document.write( "You can check (2)\r
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