document.write( "Question 879989: Two brothers start at same time from two places 20 kms apart. If they walk in same
\n" ); document.write( "direction, elder brother overtakes the younger in 10 hrs, but if they walk in opposite
\n" ); document.write( "directions, they meet in 2 hrs. Find the rates at which they walk.
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Algebra.Com's Answer #531184 by josmiceli(19441)\"\" \"About 
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Let the rate of the elder brother = \"+r%5B1%5D+\"
\n" ); document.write( "Let the rate of the younger brother = \"+r%5B2%5D+\"
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\n" ); document.write( "The elder brother has to have the faster rate
\n" ); document.write( "in order to catch up with the younger brother
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\n" ); document.write( "Also, when they walk in opposite directions,
\n" ); document.write( "they must be walking towards each other, or
\n" ); document.write( "else they would never meet
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\n" ); document.write( "Let \"+d+\" = distance the elder brother has
\n" ); document.write( "to travel to catch younger brother
\n" ); document.write( "Walking in same direction:
\n" ); document.write( "Equation for younger brother:
\n" ); document.write( "(1) \"+d+-+20+=+r%5B2%5D%2A10+\"
\n" ); document.write( "Equation for elder brother:
\n" ); document.write( "(2) \"+d+=+r%5B1%5D%2A10+\"
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\n" ); document.write( "Walking towards each other:
\n" ); document.write( "Think of this as the elder brother moving
\n" ); document.write( "at the sum of their speeds and the
\n" ); document.write( "younger brother not moving
\n" ); document.write( "(3) \"+20+=+%28+r%5B1%5D+%2B+r%5B2%5D+%29%2A2+\"
\n" ); document.write( "------------------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+10r%5B1%5D+-+20+=+10r%5B2%5D+\"
\n" ); document.write( "(1) \"+10%2A%28+r%5B1%5D+-+r%5B2%5D+%29+=+20+\"
\n" ); document.write( "(1) \"+r%5B1%5D+-+r%5B2%5D+=+2+\"
\n" ); document.write( "and
\n" ); document.write( "(3) \"+r%5B1%5D+%2B+r%5B2%5D+=+10+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "Add (1) and (3)
\n" ); document.write( "\"+2r%5B1%5D+=+12+\"
\n" ); document.write( "\"+r%5B1%5D+=+6+\"
\n" ); document.write( "and, since
\n" ); document.write( "(3) \"+r%5B1%5D+%2B+r%5B2%5D+=+10+\"
\n" ); document.write( "(3) \"+6+%2B+r%5B2%5D+=+10+\"
\n" ); document.write( "(3) \"+r%5B2%5D+=+4+\"
\n" ); document.write( "---------------
\n" ); document.write( "The eldest brother's rate is 6 km/hr
\n" ); document.write( "The younger brother's rate is 4 km/hr
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\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+r%5B1%5D%2A10+\"
\n" ); document.write( "(2) \"+d+=+60+\" km
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+-+20+=+r%5B2%5D%2A10+\"
\n" ); document.write( "(1) \"+d+=+4%2A10+%2B+20+\"
\n" ); document.write( "(1) \"+d+=+60+\" km
\n" ); document.write( "OK\r
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