document.write( "Question 879941: in 12 year man will be 3 times old as son.the difference of their agesbe 30 year.find there present ages? \n" ); document.write( "
Algebra.Com's Answer #531144 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "Let x and y represent Dad's and Son's ages
\n" ); document.write( "Question States***
\n" ); document.write( "x + 12 = 3(y+12), x = \"3y%2B24\"
\n" ); document.write( " x - y = 30 |Substitute \"3y%2B24\"for x
\n" ); document.write( " (3y+24) - y = 30
\n" ); document.write( " 2y = 6
\n" ); document.write( " y = 3, age of son. Dad is 33 \"3%2B30\"
\n" ); document.write( "CHECKING our answer***in 12 years...
\n" ); document.write( " 45 = 3•15
\n" ); document.write( "Wish You the Best in your Studies.
\n" ); document.write( " \n" ); document.write( "
\n" );