document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=879877>Question 879877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	The surface area of two similar cylinders are 879 cm2 and 220 cm2. If the volume of the smaller cylinder is 314 cm3, find the volume of the larger cylinder.\r<BR>\n" );
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document.write( "I first divided 879/220 and got 3.995 which I rounded to 4<BR>\n" );
document.write( "I know 4 = 2^2 so my scale factor is 2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531117 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The smaller cylinder:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=highlight_green%282pi%2Ar%5E2%2Bh2pi%2Ar=220%29 ALIGN=MIDDLE  ALT=\"A=highlight_green%282pi%2Ar%5E2%2Bh2pi%2Ar=220%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V=highlight_green%28h%2Api%2Ar%5E2=314%29 ALIGN=MIDDLE  ALT=\"V=highlight_green%28h%2Api%2Ar%5E2=314%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Using volume equation, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=314%2F%28pi%2Ar%5E2%29 ALIGN=MIDDLE  ALT=\"h=314%2F%28pi%2Ar%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >; substitute into the area equation:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%5E2%2B%28314%2F%28pi%2Ar%5E2%29%292pi%2Ar=314 ALIGN=MIDDLE  ALT=\"2pi%2Ar%5E2%2B%28314%2F%28pi%2Ar%5E2%29%292pi%2Ar=314\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%5E2%2B628%2Fr=314 ALIGN=MIDDLE  ALT=\"2pi%2Ar%5E2%2B628%2Fr=314\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%5E3%2B628=314r ALIGN=MIDDLE  ALT=\"2pi%2Ar%5E3%2B628=314r\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%5E3-314r%2B628=0 ALIGN=MIDDLE  ALT=\"2pi%2Ar%5E3-314r%2B628=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28pi%2Ar%5E3-157r%2B314=0%29 ALIGN=MIDDLE  ALT=\"highlight%28pi%2Ar%5E3-157r%2B314=0%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >---Obviously not yet finished, but a graphing calculator might help in getting a value for r, the diameter for the small cylinder; and from this, the length of the cylinder can be found.  The ratio between the two cylinders can then be used.\r<BR>\n" );
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document.write( "(Roots appear near 2.20 and 5.70; evaluate each carefully and judge if useful). </SPAN>\n" );
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