document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=879876>Question 879876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the vertex, focus and directrix of the parabola and sketch the graph \r<BR>\n" );
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document.write( "4x-y^2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531102 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Handling this question might be easier using the already derived equation for the simpler model of x=y^2.  Taking this simple form as 4x=y^2 to get directrix and focus depends on knowing how the equation was formed from knowing directrix and focus.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4px=y%5E2 ALIGN=MIDDLE  ALT=\"4px=y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > is an equation of a parabola with p being distance from vertex to directrix and distance from vertex to focus.  Your given equation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2A1%2Ax=y%5E2 ALIGN=MIDDLE  ALT=\"4%2A1%2Ax=y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  The parabola is horizontal with a vertex (0,0).  Focus is (0,1) and directrix is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-1 ALIGN=MIDDLE  ALT=\"x=-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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