document.write( "Question 879809: answer for a soup company decides to increase the height of its cans by 40% but to keep the volume the same. approximately how much the radius of the can be decreaed to keep the volume constant? \n" ); document.write( "
Algebra.Com's Answer #531098 by ankor@dixie-net.com(22740)\"\" \"About 
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answer for a soup company decides to increase the height of its cans by 40% but to keep the volume the same.
\n" ); document.write( " approximately how much the radius of the can be decreased to keep the volume constant?
\n" ); document.write( ":
\n" ); document.write( "One way is to assume some values and find the % decrease in the radius
\n" ); document.write( "Original can 4 cm radius, 10 cm height
\n" ); document.write( "New can r = radius, 14 cm height
\n" ); document.write( "We can ignore pi here
\n" ); document.write( "14r^2 = 4^2*10
\n" ); document.write( "14r^2 = 160
\n" ); document.write( "r^2 = 160/14
\n" ); document.write( "r^2 = 11.4286
\n" ); document.write( "r = \"sqrt%2811.4286%29\"
\n" ); document.write( "r = 3.38cm is the new radius
\n" ); document.write( "Find the % decrease
\n" ); document.write( "4 - 3.38 = .62
\n" ); document.write( "\".62%2F4\" * 100 = 15.5% decrease \n" ); document.write( "
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