document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=879841>Question 879841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need to evaluate this and I dont know how<BR>\n" );
document.write( "51P2<BR>\n" );
document.write( "the two is at the bottom<BR>\n" );
document.write( "Thank you for help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #531078 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=531078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 51 P 2 is the same as 51*50\r<BR>\n" );
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document.write( "You start at 51. Then you count down until you have 2 numbers to multiply (the 2 is from 51P2). Another example would be 51P4 = 51*50*49*48. Notice how I started at 51 and counted down to 48 to have 4 terms multiplied out.\r<BR>\n" );
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document.write( "You could use the formula nPr = (n!)/(n-r)!, but I like the first method better. Either way is up to you.\r<BR>\n" );
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document.write( "So, 51 P 2 = 51*50 = 2550 </SPAN>\n" );
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