document.write( "Question 879833: A collection of 22 laptops include six defective laptops. If a sample of three laptops is randomly chosen from the collection, what is the probability that at least one laptop will be defective?\r
\n" ); document.write( "\n" ); document.write( "1-P(16/3 divided by 22/3)\r
\n" ); document.write( "\n" ); document.write( "I get .273, but I have been told that the answer is actually .636.\r
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Algebra.Com's Answer #531076 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The probability that you pick 3 nondefective laptops is (16/22)*(15/21)*(14/20) = 0.3636\r
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\n" ); document.write( "\n" ); document.write( "So the probability that at least 1 is defective is 1 - 0.3636 = 0.6364\r
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\n" ); document.write( "\n" ); document.write( "Round that to 3 decimal places to get 0.636
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