document.write( "Question 879742: In a fraction if the numerator is increased by 5, and the denominator is decreased by 3,the result is 1/4. But if the numerator is decreased by 22/5, and the denominator is tripled, the result is -2/5. How do I find x/y? \n" ); document.write( "
Algebra.Com's Answer #531075 by lwsshak3(11628)\"\" \"About 
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In a fraction if the numerator is increased by 5, and the denominator is decreased by 3,the result is 1/4. But if the numerator is decreased by 22/5, and the denominator is tripled, the result is -2/5. How do I find x/y?
\n" ); document.write( "***
\n" ); document.write( "let x=numerator
\n" ); document.write( "let y=denominator
\n" ); document.write( "..
\n" ); document.write( "\"%28x%2B5%29%2F%28y-3%29=1%2F4\"
\n" ); document.write( "\"%28x-%2822%2F5%29%29%2F%283y%29=-2%2F5\"
\n" ); document.write( "..
\n" ); document.write( "4x+20=y-3
\n" ); document.write( "5x-22=-6y
\n" ); document.write( "..
\n" ); document.write( "4x+23=y
\n" ); document.write( "5x-22=-6y
\n" ); document.write( "..
\n" ); document.write( "24x+138=6y
\n" ); document.write( "5x-22=-6y
\n" ); document.write( "add
\n" ); document.write( "29x+116=0
\n" ); document.write( "29x=-116
\n" ); document.write( "x=-4
\n" ); document.write( "y=4x+23=-16+23=7
\n" ); document.write( "x/y=-4/7
\n" ); document.write( "...
\n" ); document.write( "check:
\n" ); document.write( "(-4+5)/(7-3)=1/4
\n" ); document.write( "(-42/5))/(21)=-2/5\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );