document.write( "Question 879829: The area of an isoceles right triangle is 242m squared. What is the length of the triangle base? \n" ); document.write( "
Algebra.Com's Answer #531073 by jim_thompson5910(35256)\"\" \"About 
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The special formula for the area of an isoceles right triangle is\r
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\n" ); document.write( "\n" ); document.write( "A = (x^2)/2\r
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\n" ); document.write( "\n" ); document.write( "where x is the base and the height (base = height)\r
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\n" ); document.write( "\n" ); document.write( "A = (x^2)/2\r
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\n" ); document.write( "\n" ); document.write( "242 = (x^2)/2\r
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\n" ); document.write( "\n" ); document.write( "242*2 = x^2\r
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\n" ); document.write( "\n" ); document.write( "484 = x^2\r
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\n" ); document.write( "\n" ); document.write( "x^2 = 484\r
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\n" ); document.write( "\n" ); document.write( "x = sqrt(484)\r
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\n" ); document.write( "\n" ); document.write( "x = 22\r
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\n" ); document.write( "\n" ); document.write( "The base and height are 22 meters.
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