document.write( "Question 879815: 1). 3y^2 +14y+4
\n" ); document.write( "I think it is unfactorable because I tried different pairings. \r
\n" ); document.write( "\n" ); document.write( "2). 9p^2-q^2+3p
\n" ); document.write( "I think this one is also unfactorable.\r
\n" ); document.write( "\n" ); document.write( "Thank you so much!
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Algebra.Com's Answer #531065 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
Rather use discriminant to avoid testing different combinations.\r
\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc\" has a discriminant number, \"b%5E2-4ac\". If discriminant is a square integer, then the quadratic trinomial is factorable.\r
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\n" ); document.write( "\n" ); document.write( "3y^2+14y+4,
\n" ); document.write( "check \"14%5E2-4%2A3%2A4=196-48=148\".
\n" ); document.write( "What happens if you form sqrt(148)?
\n" ); document.write( "\"2%2Asqrt%2837%29\", irrational; so the roots of the polynomial are also irrational, so 3y^2+14y+4 is not factorable (unless you want irrational constants in your binomials).\r
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\n" ); document.write( "\n" ); document.write( "9p^2-p+3p, assuming you made a misprint when you showed -q;
\n" ); document.write( "Check yourself... discriminant, \"%28-1%29%5E2-4%2A9%2A3\"....
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