document.write( "Question 879729: The third and fourth terms of a sequence are 101 and 83. If the first differences are a constant, find the first 5 terms in the sequence?
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Algebra.Com's Answer #530991 by ewatrrr(24785) $\"\"$ $\"About$

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$\"a%5Bn%5D+=+a%5B1%5D+%2B+%28n-1%29d\"$
\n" ); document.write( " $\"a%5B3%5D+=+a%5B1%5D+%2B+%282%29d+=+101\"$
\n" ); document.write( " $\"a%5B4%5D+=+a%5B1%5D+%2B+%283%29d+=+83\"$ SUBTRACT EQs
\n" ); document.write( " -d = 18, d = -18 and a[1] = 137 $\"a%5B1%5D+%2B+%282%29%28-18%29+=+101\"$
\n" ); document.write( "{137, 119, 101, 83, 65,...}
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