document.write( "Question 879728: How do you find two consecutive odd integers whose product is 36? \n" ); document.write( "
Algebra.Com's Answer #530990 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
n (n+2)= 36
\n" ); document.write( "n^2 + 2n - 36 = 0 Not going to work..solution does not yield an Integer.
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B2x%2B-36+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A1%2A-36=148\".
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\n" ); document.write( " Discriminant d=148 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+148+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+148+%29%29%2F2%5C1+=+5.08276253029822\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+148+%29%29%2F2%5C1+=+-7.08276253029822\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B2x%2B-36\" can be factored:
\n" ); document.write( " \"1x%5E2%2B2x%2B-36+=+1%28x-5.08276253029822%29%2A%28x--7.08276253029822%29\"
\n" ); document.write( " Again, the answer is: 5.08276253029822, -7.08276253029822.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B2%2Ax%2B-36+%29\"
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