document.write( "Question 879705: Show that the equation 2^x+1 + 2^x-1= 160 can be written in the form 2.5 x 2^x=160. Hence find the value of x which satisfies the equation. \r
\n" ); document.write( "\n" ); document.write( "thanks
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #530980 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"2%5E%28x%2B1%29=2%5Ex%2A2%5E1=2%2A2%5Ex\"
\n" ); document.write( "\"2%5E%28x-1%29=2%5Ex%2A2%5E%28-1%29=%281%2F2%292%5Ex\"
\n" ); document.write( "So then,
\n" ); document.write( "\"2%5E%28x%2B1%29%2B2%5E%28x-1%29=150\"
\n" ); document.write( "\"2%2A2%5Ex%2B%281%2F2%29%2A2%5Ex=160\"
\n" ); document.write( "\"%282%2B1%2F2%29%2A2%5E%28x%29=160\"
\n" ); document.write( "\"%285%2F2%292%5E%28x%29=160\"
\n" ); document.write( "\"2%5Ex=320%2F5\"
\n" ); document.write( "\"2%5Ex=84\"
\n" ); document.write( "\"x=log%28%2884%29%29%2Flog%28%282%29%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );