document.write( "Question 879659: Tom and Barbara live 415 mi apart. They leave their homes and travel toward one another. Tom travels at an average speed of 60 mph and Barbara travels at an average speed of 65 mph. Tom leaves 20 minutes before Barbara. How long will they each travel before they meet? \n" ); document.write( "
Algebra.Com's Answer #530964 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Tom and Barbara live 415 mi apart. They leave their homes and travel toward one another. Tom travels at an average speed of 60 mph and Barbara travels at an average speed of 65 mph. Tom leaves 20 minutes before Barbara. How long will they each travel before they meet? \n" ); document.write( "*** \n" ); document.write( "let x=Barbara's travel time in hours \n" ); document.write( "x+1/3=Tom's travel time in hours \n" ); document.write( "Distance traveled=speed*travel time \n" ); document.write( ".. \n" ); document.write( "65x+60(x+1/3)=415 \n" ); document.write( "65x+60x+20=415 \n" ); document.write( "125x=395 \n" ); document.write( "x=3.16 \n" ); document.write( "x+1/3=3.49 \n" ); document.write( "Barbara's travel time=3.16 hrs \n" ); document.write( "Tom's travel time=3.49 hrs \n" ); document.write( " |