document.write( "Question 879542: 5x - 5y = 10
\n" ); document.write( "3x - 2y = 2\r
\n" ); document.write( "\n" ); document.write( "Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. \r
\n" ); document.write( "\n" ); document.write( "Part B: Show that the equivalent system has the same solution as the original system of equations.
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Algebra.Com's Answer #530961 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Your part A and part B are a little difficult to follow but maybe this will help:\r
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\n" ); document.write( "\n" ); document.write( "\"5x-5y=10\" can be simplified, dividing left and right members by 5, to give \"x-y=2\".\r
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\n" ); document.write( "\n" ); document.write( "Your system is then equivalent to
\n" ); document.write( "\"x-y=2\" and \"3x-2y=2\".
\n" ); document.write( "You can solve this system with the Elimination Method. The simplest way to start this is to try to match the coefficient on y in the second equation of the system. The way to do this is multiply the left and right members of the first equation by 2, yielding the system: \"2x-2y=4\" AND \"3x-2y=2\".
\n" ); document.write( "Now, simply subtract one equation from the other equation:
\n" ); document.write( "\"2x-2y-%283x-2y%29=4-2\"
\n" ); document.write( "\"2x-2y-3x%2B2y=2\"
\n" ); document.write( "\"-x%2B0=2\"
\n" ); document.write( "\"highlight%28x=-2%29\"
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\n" ); document.write( "Now, you might prefer not to again use elimination of x in order to find y; but instead to simply substitute for x=-2 in either equation of the system and solve for y.\r
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\n" ); document.write( "\n" ); document.write( "... y=-4.
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