document.write( "Question 879650: A car dealer has kept records of the customers who visited his showroom. 30% of the customers who visited his showroom were women. Furthermore, his records show that 24% of the women who visited his showroom ended up buying a car while only 14% of the men ended up buying a car. If, while away for a lunch break, a customer came to the showroom and talk to the assistant but did not buy a car, what is the probability that the customer was a man? \n" ); document.write( "
Algebra.Com's Answer #530950 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 1-.14=.86 of men who come in don't buy a car. \n" ); document.write( "1-.24=.76 of women who come in don't buy a car. \n" ); document.write( ". \n" ); document.write( ".7*.86=.602 probability that a man came in and didn't buy a car. \n" ); document.write( ".3*.76=.228 probability that a woman came in and didn't buy a car. \n" ); document.write( ".602+.228=.83 Probability of someone coming in and not buying a car. \n" ); document.write( ".602/.83 = 301/415 =~ 72.5% the probability that the customer was a man. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |