document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74104>Question 74104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you help me to explain this equation?\r<BR>\n" );
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document.write( "If f(x)=x-1/x+1 then f(x)+f(1/x)=\r<BR>\n" );
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document.write( "this is a homework assignment..but not in our book..thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53094 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f(x)= x-1/x+1 then f(x)+ f(1/x) =<BR>\n" );
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document.write( "Deal with f(1/x) first, substitute (1/x) for x in f(x) = x - (1/x) + 1:<BR>\n" );
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document.write( "f(1/x) = (1/x) - 1/(1/x) + 1<BR>\n" );
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document.write( "1/(1/x) is equal to x so you have:<BR>\n" );
document.write( "f(1/x) = (1/x) - x + 1<BR>\n" );
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document.write( "It wants f(x) + f(1/x); we just found f(1/x) and f(x) was given originally <BR>\n" );
document.write( "so we have<BR>\n" );
document.write( "(x - (1/x) + 1) + ((1/x) - x + 1) =<BR>\n" );
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document.write( "Combine like terms<BR>\n" );
document.write( "x - x - (1/x) + (1/x) + 1 + 1 = 2 is the solution<BR>\n" );
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document.write( "Did this help? </SPAN>\n" );
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