document.write( "Question 879591: A motorist traveled from Town A to Town B. After traveling 13 of the distance for [4] the journey at an average speed of 45 km/h, he continued to travel another 480
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Algebra.Com's Answer #530927 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The 2nd sentence was unclear to me so I changed it to what I thought you meant.
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\n" ); document.write( "A motorist traveled from Town A to Town B.
\n" ); document.write( " After traveling 1/3 of the distance at an average speed of 45 km/h, he continued to travel another 480 km to reach Town B.
\n" ); document.write( " If his average speed for the entire journey was 54 km/h, what was his average speed for the last 2/3 of the distance?
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\n" ); document.write( "From the information given, find the total distance (d) from A to B
\n" ); document.write( "\"2%2F3\"d = 480
\n" ); document.write( "2d = 480 * 3
\n" ); document.write( "2d = 1440
\n" ); document.write( "d = 720 km
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\n" ); document.write( "Find 1/3 of the total
\n" ); document.write( "\"1%2F3\" * 720 = 240 km
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\n" ); document.write( "Let a = ave speed for the last 2/3 of the journey
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\n" ); document.write( "write a time equation, time = dist/speed
\n" ); document.write( "\"240%2F45\" + \"480%2Fa\" = \"720%2F54\"
\n" ); document.write( "multiply by Least common multiple, 270a
\n" ); document.write( "270a*\"240%2F45\" + 270a*\"480%2Fa\" = 270a*\"720%2F54\"
\n" ); document.write( "cancel the denomintors
\n" ); document.write( "6a(240) + 270(480) = 5a(720)
\n" ); document.write( "1440a + 129600 = 3600a
\n" ); document.write( "129600 = 3600a - 1440a
\n" ); document.write( "129600 = 2160a
\n" ); document.write( "a = 129600/2160
\n" ); document.write( "a = 60 km/hr for last 2/3 of the journey
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\n" ); document.write( "Check this, find the times
\n" ); document.write( "240/45 = 5.33 hrs
\n" ); document.write( "480/60 = 8.00 hrs
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\n" ); document.write( "total: = 13.33 hrs
\n" ); document.write( "and
\n" ); document.write( "720/54 = 13.33 hrs
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