document.write( "Question 879608: Thanks In Advance :)\r
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document.write( "A club wants to choose a committee of 4 people from its 12 members.
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document.write( "How many ways can the committee be chosen?
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document.write( " A.
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document.write( "48
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document.write( " B.
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document.write( "11,880
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document.write( " C.
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document.write( "19,958,400
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document.write( " D.
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document.write( "495 (I think it's this one) \n" );
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Algebra.Com's Answer #530926 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! You are correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "12 C 4 = (12!)/(4!*(12-4)!) = 495\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We use a combination (instead of a permutation) since order doesn't matter. \n" ); document.write( " |