document.write( "Question 74080: Please help. What am I doing here?
\n" ); document.write( "In exercise 2, evaluate each function for the value specified.\r
\n" ); document.write( "\n" ); document.write( "f(x)=x^2-7x +10; find (a) f(0), (b) f(5), and (c) f(-2).\r
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Algebra.Com's Answer #53087 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( "\"f%28x%29=x%5E2-7x+%2B10\"\r
\n" ); document.write( "\n" ); document.write( "Find: (a) f(0), (b) f(5), and (c) f(-2)
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\n" ); document.write( "All this problem require you to do is assign values to x and solve for the given function.
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\n" ); document.write( "In (a) f(0) means go to the given function and substitute 0 for every x you find. When you
\n" ); document.write( "do that the function is:
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\n" ); document.write( "\"f%280%29=0%5E2-7%2A0+%2B10\" and this simplifies it to \"f%280%29+=+0+%2B+0+%2B10\" which reduces to:
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\n" ); document.write( "\"f%280%29+=+%2B10\"
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\n" ); document.write( "In (b) f(5) means go to the given function and replace all the x's in it with 5. When you do
\n" ); document.write( "it becomes: \"f%285%29+=+5%5E2+-+7%2A5+%2B+10+=+25+-+35+%2B+10\" which reduces to:
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\n" ); document.write( "\"f%280%29+=+25+-35+%2B+10+=+0\" so that \"f%285%29+=+0\"
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\n" ); document.write( "In (c) \"f%28-2%29+=+%28-2%29%5E2+-7%2A%28-2%29+%2B+10\" which becomes \"f%28-2%29=+4+%2B+14+%2B10\" and this
\n" ); document.write( "simplifies to \"f%28-2%29+=+28\"
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\n" ); document.write( "Hope this helps you to understand the problem.\r
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