document.write( "Question 879541: For Normal Distribution with mean μ=100 and standard deviation σ=20.
\n" ); document.write( " find probability that x will be between x1 and x2: P (x1 < x < x2).
\n" ); document.write( " Take x1 and x2 from the table below.the value of x1 is 95 and the value of x2 is 110
\n" ); document.write( " ********Here are steps to follow: convert x1 to z score z1, convert x2 to z score z2.
\n" ); document.write( " From Appendix table for Normal Distribution find area under curve
\n" ); document.write( " to the left of z1 and to the left of z2.
\n" ); document.write( " That will give you P (z < z1) and P (z < z2).
\n" ); document.write( " Then use formula: P (A < x < B) = P (z1 < z < z2) = P (z < z2) - P (z < z1) \n" ); document.write( "
Algebra.Com's Answer #530857 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi
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document.write( "Population: μ=100 and standard deviation σ=20.
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document.write( " P (A < x < B) = P (z1 < z < z2) = P (z < z2) - P (z < z1)
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document.write( " P (95 < x < 110) = 
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document.write( "P (-5/20 < z < 10/20) = P (x < .5) - P (z < .25) = .6815-.5987 = .0828
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document.write( "Below: find z-scores:  P (95 < x < 110) is the area under normal curve between z-values
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document.write( "For the normal distribution: Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  
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document.write( "Area under the standard normal curve to the left of the particular z is P(z)
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document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50%  to the right
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