document.write( "Question 879525: Thank you for taking my question. I believe it uses combinations and is a bit tricky:\r
\n" ); document.write( "\n" ); document.write( "The possibility that a basketball player will make a given free throw is 3/5. To find the probability that the player makes exactly 9 out of his next 10 free throws, evaluate the term 10C9 (3/5)^9(2/5)^1 in the expansion of (3/5 + 2/5)^10
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Algebra.Com's Answer #530851 by ewatrrr(24785)\"\" \"About 
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Previously Posted
\n" ); document.write( "Using \"P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+\"
\n" ); document.write( "p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p = 3/5 and q = 2/5, n = 10
\n" ); document.write( "\"nCx+=+%28n%21%29%2Fx%21%28n+-+x%29%21%29\"
\n" ); document.write( "P(x = 9) = 10C9(3/5)^9(2/5)^1 = 10(3/5)^9(2/5)^1 = .0403 0r 4.03% chance
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