document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=879477>Question 879477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "1.Find the (x,y) coordinate of the maximum or minimum value<BR>\n" );
document.write( "of the following quadratic equation: 0.125x2 - 1.625x + 5 = y<BR>\n" );
document.write( "Express the y-coordinate value to the nearest thousandth.\r<BR>\n" );
document.write( "\n" );
document.write( "2.The coordinate determined in the problem above is a(n)<BR>\n" );
document.write( "    a. mimumum value<BR>\n" );
document.write( "    b. maximum value<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530812 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = 0.125x2 - 1.625x + 5  Parabola Opening Upward .125>0<BR>\n" );
document.write( "y = 0.125(x-13/2)^2 + 5.28125 + 5<BR>\n" );
document.write( " minimum(6.5, 10.281) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );