document.write( "Question 879299: Solve the inequality (x + 3)(5 - x) < 0. Give your solution in interval notation \n" ); document.write( "
Algebra.Com's Answer #530700 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Two obvious critical values for x are -3 and 5. Check a value in each interval.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-oo, -3), pick -4=x. \n" ); document.write( "(-)(+)=(-)<0 TRUE.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-3, 5), pick x=0. \n" ); document.write( "(+)(+)=(+)<0, basically FALSE.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(5, oo), pick 10=x. \n" ); document.write( "(+)(-)=(-)<0 TRUE.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Statement is true for x in (-oo, -3) OR (5, oo). \n" ); document.write( " |