document.write( "Question 879337: 2y^2+17y-9\r
\n" ); document.write( "\n" ); document.write( "when i find the common factors and write out the equation which i wrote down, (1y+9)(2y1-1) i know it isnt correct.
\n" ); document.write( "i just have a feeling i am missing a vital and very simple part of finding the answer. please help
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Algebra.Com's Answer #530679 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
What you suggest you want is to factorize \"2y%5E2%2B17y-9\". This is an expression, but NOT an equation. There are a few combinations of numbers to try, and maybe one of them will work; but only one of them at most, or maybe none of them.\r
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\n" ); document.write( "\n" ); document.write( "(a+h)(b-k) is supposed to produce the constant term of -9. These would be possible binomial combinations to check:\r
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\n" ); document.write( "\n" ); document.write( "(2y-1)(y+9)\r
\n" ); document.write( "\n" ); document.write( "(2y+1)(y-9)\r
\n" ); document.write( "\n" ); document.write( "(2y-9)(y+1)\r
\n" ); document.write( "\n" ); document.write( "(2y+1)(y-9)\r
\n" ); document.write( "\n" ); document.write( "(2y+3)(y-3)\r
\n" ); document.write( "\n" ); document.write( "(2y-3)(y+3)\r
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\n" ); document.write( "\n" ); document.write( "They all will produce the -9, but which one if any will reproduce the +17y?
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\n" ); document.write( "In fact, the first one listed gives you this:
\n" ); document.write( "\"highlight_green%28%282y-1%29%28y%2B9%29%29\"---This factorization works.
\n" ); document.write( "\"%282y-1%29y%2B%282y-1%29%2A9\"
\n" ); document.write( "\"2y%5E2-y%2B18y-9\"
\n" ); document.write( "\"2y%5E2%2B18y-y-9\"
\n" ); document.write( "\"2y%5E2%2B%2818-1%29y-9\"
\n" ); document.write( "\"highlight_green%282y%5E2%2B17y-9%29\"
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