document.write( "Question 879237: the area of a rectangle is 27yd^2,and the length of the rectangle is 3yd less than twice the width.Find the dimensions \n" ); document.write( "

Algebra.Com's Answer #530619 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "A = Lw = (2w-3)w = 27yd^2
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document.write( "          2w^2 - 3w - 27 = 0 
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document.write( "         (2w -9)(w  + 3) = 0,  w = 9/2yd  and L = 6yd\r
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