document.write( "Question 879009: Write the equation of a hyperbola with vertices (3, -1) and (3, -9) and co-vertices (-6. -5) and (12, -5). \n" ); document.write( "
Algebra.Com's Answer #530510 by lwsshak3(11628)\"\" \"About 
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Write the equation of a hyperbola with vertices (3, -1) and (3, -9) and co-vertices (-6. -5) and (12, -5).
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\n" ); document.write( "Given hyperbola has a vertical transverse axis:
\n" ); document.write( "Its standard form of equation: \"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\", (h,k)=coordinates of center
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "y-coordinate of center=-5 (midpoint of -1 and -9 on the vertical transverse axis)
\n" ); document.write( "x-coordinate of center=3 (midpoint of -6 and 12 on the conjugate axis)
\n" ); document.write( "center: (3,-5)
\n" ); document.write( "length of vertical transverse axis=8(-1 to -9)=2a
\n" ); document.write( "a=4
\n" ); document.write( "a^2=16
\n" ); document.write( "length of conjugate axis=18(-6 to 12)=2b
\n" ); document.write( "b=9
\n" ); document.write( "b^2=81
\n" ); document.write( " equation: \"%28y%2B5%29%5E2%2F16-%28x-3%29%5E2%2F81=1\"
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