document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=879063>Question 879063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves the station and travels north at 85 km/hr and four hours later a second train leaves on a parallel track and travels north at 125 km/hr and how far from the station will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530497 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A train leaves the station and travels north at 85 km/hr and four hours later a second train leaves on a parallel track and travels north at 125 km/hr and how far from the station will they meet?<BR>\n" );
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document.write( "let x=travel time of 2nd train<BR>\n" );
document.write( "x+4=travel time of 1st train<BR>\n" );
document.write( "distance=speed*travel time (same for both trains)<BR>\n" );
document.write( "85(x+4)=125x<BR>\n" );
document.write( "85x+340=125x<BR>\n" );
document.write( "40x=340<BR>\n" );
document.write( "x=8.5 hrs<BR>\n" );
document.write( "125*8.5=1062.5<BR>\n" );
document.write( "how far from the station will they meet? 1062.5 km \r<BR>\n" );
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document.write( " </SPAN>\n" );
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