document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=879051>Question 879051</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The directions say to solve the equation for x.\r<BR>\n" );
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document.write( "-4+log9(2x)=-5\r<BR>\n" );
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document.write( "That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions on how to solve it? I have a final tomorrow and I totally forgot how to solve this one. I tried to solve it and I have the answer because they are in the back of packet I received, but I need to know how to do it.\r<BR>\n" );
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document.write( "Thank you for your time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530493 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  solve the equation for x. <BR>\n" );
document.write( "-4+log9(2x)=-5 <BR>\n" );
document.write( "log9(2x)=-1<BR>\n" );
document.write( "convert to exponential form: (base(9) raised to log of the number(-1)=number(2x)<BR>\n" );
document.write( "9^-1=2x<BR>\n" );
document.write( "2x=1/9<BR>\n" );
document.write( "x=1/18 </SPAN>\n" );
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