document.write( "Question 878926: Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −one half. Write in standard form.\r
\n" ); document.write( "\n" ); document.write( "I got as far as finding a by graphing the focus and directrix to find the vertex then I found the focal length. Which is .25=p and by putting it into the equation for a=1/(4p. So I know a is equal to one but I am having trouble figuring out how to do the rest of the problem.
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Algebra.Com's Answer #530394 by ewatrrr(24785)\"\" \"About 
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focus at (2, −1) and a directrix of y = -1/2
\n" ); document.write( "This tells us the parabola opens downward as directrix is above focus
\n" ); document.write( "also tells us the V(2, -3/4) \"%28-1-1%2F2%29%2F2+=+-3%2F4\" where p = -1/4
\n" ); document.write( "a = 1/(4p), a = 1/(4(-1/4)) = -1
\n" ); document.write( "\"y=+-%28x-2%29%5E2+-3%2F4\" is the Vertex form, Standard Form is \"%28x-2%29%5E2+=+-%28y%2B3%2F4%29\"
\n" ); document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0), \"y=a%28x-h%29%5E2+%2Bk\"
\n" ); document.write( "where(h,k) is the vertex and x = h is the Line of Symmetry
\n" ); document.write( " a = 1/(4p), where the focus is (h,k + p)and Directrix y = (k - p)
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