document.write( "Question 878926: Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −one half. Write in standard form.\r
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document.write( "I got as far as finding a by graphing the focus and directrix to find the vertex then I found the focal length. Which is .25=p and by putting it into the equation for a=1/(4p. So I know a is equal to one but I am having trouble figuring out how to do the rest of the problem. \n" );
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Algebra.Com's Answer #530394 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! focus at (2, −1) and a directrix of y = -1/2 \n" ); document.write( "This tells us the parabola opens downward as directrix is above focus \n" ); document.write( "also tells us the V(2, -3/4) \n" ); document.write( "a = 1/(4p), a = 1/(4(-1/4)) = -1 \n" ); document.write( " \n" ); document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0), \n" ); document.write( "where(h,k) is the vertex and x = h is the Line of Symmetry \n" ); document.write( " a = 1/(4p), where the focus is (h,k + p)and Directrix y = (k - p) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |