document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73981>Question 73981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> all about the area of the circle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53038 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the radius of a circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r ALIGN=MIDDLE  ALT=\"r\"   DISABLED_style= \"max-width:90%; height:auto;\" > then the area of the circle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi=22%2F7+=+3.14 ALIGN=MIDDLE  ALT=\"pi=22%2F7+=+3.14\"   DISABLED_style= \"max-width:90%; height:auto;\" > approx.\r<BR>\n" );
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document.write( "Example:<BR>\n" );
document.write( "If the diameter of a circle is 14 cm, then the radius is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=14%2F2=7 ALIGN=MIDDLE  ALT=\"r=14%2F2=7\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm. The area of the circle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A7%5E2+=+%2822%2F7%29%2A7%5E2+=+22%2A7+=+154 ALIGN=MIDDLE  ALT=\"pi%2A7%5E2+=+%2822%2F7%29%2A7%5E2+=+22%2A7+=+154\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq. cm. </SPAN>\n" );
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