document.write( "Question 878782: A cube has all of its sides painted in blue and then is cut into 1000 cubes of the same size. All cubes are placed in an urn and are thoroughly mixed, so that the probability of being randomly picked from the urn is the same for all cubes. What is the probability that a randomly picked cube has at least one of its sides painted blue? \n" ); document.write( "
Algebra.Com's Answer #530368 by KMST(5328)![]() ![]() You can put this solution on YOUR website! After you cut the cube into 1000 smaller cubes of the same size, you notice that each original edge has been split into 10 small cube edges, and each blue face has been split into 100 small cube faces. \n" ); document.write( "We could peel away all the partially painted little cubes on the outside of the original cube, put them aside on a pile and count them. \n" ); document.write( "We would find that there are \n" ); document.write( "The \"core\" unpainted cube left over has edges made up of o small cube edges, and contains the remaining \n" ); document.write( " \n" ); document.write( "When all small cubes are placed in the urn and mixed, \n" ); document.write( " \n" ); document.write( "so the probability that a randomly picked small cube has at least one of its sides painted blue is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "How can we count the partially painted little cubes? \n" ); document.write( "I just calculated the number of small cubes in the \"core\" edge left after peeling off the painted outside cubes, and subtracted the result from 1000. \n" ); document.write( "Since I had peeled away \n" ); document.write( "the \n" ); document.write( "the \n" ); document.write( "the \n" ); document.write( "what was left was an unpainted cube with \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( "Then \n" ); document.write( " \n" ); document.write( "I could also have counted the partially painted little cubes as I peeled them off the original, larger cube. \n" ); document.write( "There were \n" ); document.write( "After taking the corner small cubes off, I took off the remaining small cubes on the 12 edges. There were 8 left on each edge, and each one had 2 painted faces. \n" ); document.write( "There were \n" ); document.write( "Finally, I took of the small partially painted cubes left in the middle of each of the 6 faces of the cube. They had only one face painted, and they were covering the 8 small cube by 8 small cube square in the middle of each face. \n" ); document.write( "There were \n" ); document.write( "The total number of peeled off partially painted small cubes was \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I could also have counted the partially painted little cube faces, and then corrected for the double and triple contributions to that total from the little cubes with more than one painted face. \n" ); document.write( "Each of the 6 large cube faces is s;pit into \n" ); document.write( "There were \n" ); document.write( "There are also \n" ); document.write( "Calculated that way, the total number of partially painted small cubes is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I like it when I can get the same result two or three different ways. It makes me more confident that I did not make a mistake. \n" ); document.write( " |