document.write( "Question 878759: A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fifteen less than twice as many nickels as quarters. If the face value of the entire collection was $40.40. How many of each kind of the coin was there? \n" ); document.write( "
Algebra.Com's Answer #530366 by lwsshak3(11628)\"\" \"About 
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A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fifteen less than twice as many nickels as quarters. If the face value of the entire collection was $40.40. How many of each kind of the coin was there?
\n" ); document.write( "***
\n" ); document.write( "let x=number of dimes
\n" ); document.write( "5x=number of quarters
\n" ); document.write( "2*5x-15=10x-15=number of nickels
\n" ); document.write( ".10x+.25*5x+.05(10x-15)+6.00=40.40
\n" ); document.write( ".10x+1.25x+.50x-.75+6.00=40.40
\n" ); document.write( "1.85x=35.15
\n" ); document.write( "x=19
\n" ); document.write( "5x=95
\n" ); document.write( "10x-15=175
\n" ); document.write( "..
\n" ); document.write( "number of dimes=19
\n" ); document.write( "number of quarters=95
\n" ); document.write( "number of nickels=175
\n" ); document.write( "number ofpennies=600
\n" ); document.write( "
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