document.write( "Question 878759: A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fifteen less than twice as many nickels as quarters. If the face value of the entire collection was $40.40. How many of each kind of the coin was there? \n" ); document.write( "
Algebra.Com's Answer #530366 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fifteen less than twice as many nickels as quarters. If the face value of the entire collection was $40.40. How many of each kind of the coin was there? \n" ); document.write( "*** \n" ); document.write( "let x=number of dimes \n" ); document.write( "5x=number of quarters \n" ); document.write( "2*5x-15=10x-15=number of nickels \n" ); document.write( ".10x+.25*5x+.05(10x-15)+6.00=40.40 \n" ); document.write( ".10x+1.25x+.50x-.75+6.00=40.40 \n" ); document.write( "1.85x=35.15 \n" ); document.write( "x=19 \n" ); document.write( "5x=95 \n" ); document.write( "10x-15=175 \n" ); document.write( ".. \n" ); document.write( "number of dimes=19 \n" ); document.write( "number of quarters=95 \n" ); document.write( "number of nickels=175 \n" ); document.write( "number ofpennies=600 \n" ); document.write( " |