document.write( "Question 74007: \n" ); document.write( "
Algebra.Com's Answer #53036 by psbhowmick(878)\"\" \"About 
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a) Common ratio = \"2%2F1+=+4%2F2+=+8%2F4+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "b) The n-th term is given by \"t%5Bn%5D+=+ar%5E%28n-1%29\" where \"a\" is the first term and \"r\" is the common ratio.
\n" ); document.write( "Here n = 24, a = 1, r = 2.
\n" ); document.write( "So, \"t%5B24%5D+=+1%2A2%5E%2824-1%29+=+2%5E23%29\"\r
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\n" ); document.write( "\n" ); document.write( "c) The sum of the first n-terms is given by \"S%5Bn%5D+=+a%28r%5En-1%29%2F%28r-1%29\".
\n" ); document.write( "Here n = 10, a = 1, r = 2.
\n" ); document.write( "So \"S%5B10%5D+=+1%282%5E10-1%29%2F%282-1%29+=+%282%5E10-1%29%2F1+=+2%5E10-1+=+1024+-+1+=+1023\"
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