document.write( "Question 74016: (4x+y)(2x squared-xy+5y squared) find the product \n" ); document.write( "
Algebra.Com's Answer #53030 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
\"%284x%2By%29%2A%282x%5E2-xy+%2B5y%5E2%29\"
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\n" ); document.write( "Here's the general plan to find the product. Use each term in the first set of parentheses
\n" ); document.write( "one at a time and multiply it times each of the three terms in the second set of parentheses.
\n" ); document.write( "Then add all the resulting terms from both multiplications. Finally look for common terms
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\n" ); document.write( "Following that plan, let's multiply 4x times every term in the second set of parentheses.
\n" ); document.write( "(Remember that you will add exponents if the term from the second set of parentheses
\n" ); document.write( "already has an x in it.)
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\n" ); document.write( "Next multiply the three terms in the second set of parentheses by the +y from the first
\n" ); document.write( "set of parentheses to get:
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\n" ); document.write( "Add the results of the two multiplications together to get:
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\n" ); document.write( "\"8x%5E3+-4x%5E2y+%2B+20xy%5E2+%2B+2x%5E2y+-+xy%5E2+%2B5y%5E3\"
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\n" ); document.write( "Now look for common terms that can be combined:
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\n" ); document.write( "How about \"-4x%5E2y+\" and \"2x%5E2y\". These add together to \"-2x%5E2y\". When you
\n" ); document.write( "replace these two terms with the single resulting term the answer reduces to:
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\n" ); document.write( "\"8x%5E3+-2x%5E2y+%2B+20xy%5E2+-+xy%5E2+%2B5y%5E3\"
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\n" ); document.write( "Next, notice the two terms that contain \"xy%5E2\". Combining these results in:
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\n" ); document.write( "\"20xy%5E2+-+xy%5E2+=+19xy%5E2\"
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\n" ); document.write( "and substituting this into the answer gives:
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\n" ); document.write( "\"8x%5E3+-2x%5E2y+%2B+19xy%5E2+%2B5y%5E3\"
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\n" ); document.write( "That's it. There are no more common terms so this is the answer to your multiplication
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\n" ); document.write( "Hope that you can track this.
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