document.write( "Question 74027: how do i do this problem 2y-12>negative 32 \n" ); document.write( "
Algebra.Com's Answer #53029 by stanbon(75887)\"\" \"About 
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2y-12>negative 32
\n" ); document.write( "Add 12 to both sides to get:
\n" ); document.write( "2y > -32+12
\n" ); document.write( "2y > -20
\n" ); document.write( "Divide both sides by 2 to get:
\n" ); document.write( "y > -10
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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