document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=878789>Question 878789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone help me with this problem?\r<BR>\n" );
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document.write( "log(x^2+6) - log(x+1) = 2 + log(x-1)\r<BR>\n" );
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document.write( "The book says that the answer is the sqrt (106/99) or approximately 1.03\r<BR>\n" );
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document.write( "I need to know the steps in completing this problems so I can learn how to do it for the test.\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #530278 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=530278\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(x^2+6) - log(x+1) = 2 + log(x-1)<BR>\n" );
document.write( "log(x^2+6)-log(x+1)-log(x-1)=2<BR>\n" );
document.write( "log(x^2+6)-(log((x+1)(x-1))=2<BR>\n" );
document.write( "log((x^2+6)/((x+1)(x-1))=2<BR>\n" );
document.write( "Assuming the base is 10, the exponential form is<BR>\n" );
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document.write( "Is that enough for you to continue and finish? </SPAN>\n" );
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