document.write( "Question 878779: How do I find the focus of the parabola x-m=-2((y+4)^2)=3? \n" ); document.write( "
Algebra.Com's Answer #530265 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi, Previously Posted
\n" ); document.write( "x-3=-2((y+4)^2)=3 ??? too many = signs
\n" ); document.write( "Anyhow: 4p = -1/2, p = -1/8 Parabola Opens left(-2 < 0) along line of symmetry: y = -4
\n" ); document.write( "Need to know the Vertex point..going to guess V(3,-4) ⇒ focus is F(2 7/8, -4)
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\n" ); document.write( "the vertex form of a Parabola opening right(a>0) or left(a<0), \"x=a%28y-k%29%5E2+%2Bh\"
\n" ); document.write( " where(h,k) is the vertex and y = k is the Line of Symmetry
\n" ); document.write( "The standard form is \"%28y+-k%29%5E2+=+4p%28x+-h%29\", 0r a = 1/4p, where the focus is (h +p,k ) With Directrix x = (k-p)
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